How do you simplify #4sqrt2(3/16) * sqrt1(2/5)#?

Answer 1
#4sqrt(2)(3/16) * 1(2/5)# #=(4sqrt(2)*3)/16*2/5# #=(12sqrt(2))/16*2/5# #=(3sqrt(2))/4*2/5# #=(6sqrt(2))/20# #=(3sqrt(2))/10#
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Answer 2

To simplify the expression 4√2(3/16) * √1(2/5), we can multiply the numbers outside the square roots and multiply the numbers inside the square roots separately.

First, multiplying the numbers outside the square roots: 4 * 3 = 12

Next, multiplying the numbers inside the square roots: √2 * √1 = √(2 * 1) = √2

Finally, multiplying the fractions inside the square roots: (3/16) * (2/5) = 6/80 = 3/40

Combining the results, we have: 12 * √2 * 3/40 = 36√2/40 = 9√2/10

Therefore, the simplified expression is 9√2/10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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