How do you simplify #[4 times (5+6)] ÷ (4² - 12)^3# using PEMDAS?

Answer 1

Answer#=11/16#

#[4*(5+6)] div (4^2-12)^3#

Work on the inside of PARENTHESIS first ....that means the innermost PARENTHESIS. So we start with 5+6 then multiply by 4, and on the other one #4^2# first before subtracting 12

#[4*11] div (16-12)^3#

At this point EXPONENTIAL first before DIVISION #44 div 4^3#

#44 div 64#

#44/64#

#11/16#

God bless. I hope you found the explanation helpful.

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Answer 2

Eva Abramson

Using PEMDAS:

Step 1: Simplify the expression inside the parentheses: (5 + 6 = 11)

Step 2: Simplify the expression within the brackets: (4 \times 11 = 44)

Step 3: Simplify the expression within the parentheses: (4^2 - 12 = 16 - 12 = 4)

Step 4: Cube the result from Step 3: (4^3 = 4 \times 4 \times 4 = 64)

Step 5: Divide the result from Step 2 by the result from Step 4: (44 \div 64 = \frac{11}{16})

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.