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How do you simplify #(-3x - 9)/-3#?

Answer 1

Savannah Anderson

#x+3#

#"each term on the numerator is divided by "-3#

#rArr(-3x)/(-3)+(-9)/(-3)#

#=(cancel(-3) x)/cancel(-3)+cancel(-9)^3/cancel(-3)^1#

#=x+3#

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Answer 2

Abigail Allen

#(-3x-9)/(-3)=color(blue)(x+3#

Make it simple:

#(-3x-9)/(-3)#

Factor out the common term #3# in the numerator.

#(-3(x+3))/(-3)#

A positive is made of two negatives.

#(3(x+3))/3#

Cancel #3# in the numerator and denominator.

#(color(red)cancel(color(black)(3))^1(x+3))/color(red)cancel(color(black)(3))^1#

Make it simple.

#x+3#

[Revise]

Alternatively, you can just observe that the denominator, or three, is the product of the divisors of both terms on the numerator.

Simply #(a+-b)/c=a/c+-b/c# Or... #(-3x-9)/(-3)=(cancel(-3) x)/(cancel(-3)) -cancel9^-3/cancel(-3)# Which gives #x-(-3)# #x+3#

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Answer 3

Eli Assouline

To simplify (-3x - 9)/-3, you divide each term inside the parentheses by -3: (-3x / -3) - (9 / -3) Simplify each term: x + 3

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Answer 4

Ethan Adkins

To simplify (-3x - 9)/-3, you divide each term in the numerator by the denominator. This results in (-3x / -3) - (9 / -3). Simplifying further, you get x + 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.