How do you simplify #(3x-8)/(6x^2-16x)# and then find the excluded values?

Answer 1

#1/(2x),x!=0#

#"simplify thedenominator by factorising"#
#(3x-8)/(2x(3x-8))larrcolor(blue)" common factor of 2x"#
#"cancel the common factor " (3x-8)#
#(cancel((3x-8)))/(2xcancel((3x-8)))=1/(2x)#
#rArr(3x-8)/(6x^2-16x)#
#=1/(2x)tox!=0larrcolor(red)" excluded value"#
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Answer 2

To simplify (3x-8)/(6x^2-16x), we can factor out a common factor of 1 from both the numerator and denominator, resulting in (3x-8)/(2x(3x-8)). The common factor of (3x-8) can be canceled out, leaving us with 1/2x as the simplified expression.

To find the excluded values, we need to identify the values of x that would make the denominator equal to zero. In this case, the denominator is 2x(3x-8), so the excluded values are x = 0 and x = 8/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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