How do you simplify #3sqrt2 + sqrt50#?

Answer 1

#3sqrt2+sqrt50=8sqrt2#

#3sqrt2+sqrt50#
= #3sqrt2+sqrt(2xxul(5xx5))#
= #3sqrt2+5sqrt2#
= #8sqrt2#
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Answer 2

To simplify 3√2 + √50, we can break down the square roots into their simplest forms.

First, we simplify √2 by recognizing that 2 is not a perfect square. Therefore, we cannot simplify it further.

Next, we simplify √50 by recognizing that 50 can be expressed as the product of a perfect square and another number. In this case, 50 = 25 * 2.

So, we can rewrite √50 as √(25 * 2). Using the property of square roots, we can split this into two separate square roots: √25 * √2.

Since √25 is equal to 5, we can simplify further to 5√2.

Therefore, 3√2 + √50 simplifies to 3√2 + 5√2, which can be combined to give us 8√2 as the final simplified form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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