How do you simplify #((3c)/-2)^-1 (d/4)^-2#?

Answer 1

# - 32/(3cd^2)#

#((3c)/(-2))^(-1) -= 1/((3c)/(-2)) -= (-2)/(3c) #.................(1)
#((d)/(4))^(-2) -= 1/((d)/(4))^(2) -= (4/d)^2 -= 4/d times 4/d -=16/(d^2)# ...... (2)

Combining ( 1 ) and ( 2) results in:

#(-2)/(3c) times 16/d^2#
# - 32/(3cd^2)#
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Answer 2

To simplify ((3c)/-2)^-1 (d/4)^-2, first, apply the negative exponent to each term inside the parentheses:

((3c)/-2)^-1 = (-2/(3c)) (d/4)^-2 = (4/d)^2

Now, apply the reciprocal of each term:

(-2/(3c))^-1 = (-3c/2) (4/d)^2 = (16/d^2)

Finally, multiply the two simplified terms together:

(-3c/2) * (16/d^2) = (-3c * 16) / (2 * d^2) = -48c / (2d^2) = -24c/d^2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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