How do you simplify #3( 5x - 6) + 2( 6+ x )#?

Answer 1

#3(5x−6)+2(6+x) = 17x - 6#

#color(red)3( 5x - 6) + color(orange)2( 6+ x )#
#= color(red)3 xx 5x + color(red)3 xx (- 6) + color(orange)2 xx 6 + color(orange)2 xx x #
#= 15x - 18 + 12 + 2x#
#= 17x - 6#
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Answer 2

#17x-6#

We want to distribute the #3# on the outside to the first term, and the #2# to its term. Here we are just multiplying, and we get
#15x-18+2x+12#
Notice, we just multiplied the #3# on the outside by the #5x# and the #-6#, and the #2# by the #6# and the #x#. In essence, what we just used is the Distributive Property.
We can now combine our variable terms to get #17x#, and our constants to get #-6#. Putting it together, we get
#17x-6#

Hope this helps!

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Answer 3

#17x-6#

#"distribute brackets and collect like tems"#
#=color(red)(15x)color(blue)(-18)color(blue)(+12)color(red)(+2x)#
#=17x-6#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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