How do you simplify #( 3 + 1) times 8 times 4# using order of operations?

Answer 1

#128#

#(3 + 1) xx 8 xx 4#

PEMDAS (the order of operations) is shown here:

Using this, the first thing to simplify is the expression inside the parenthesis:
#4 xx 8 xx 4#

Now do multiplication from left to right:
#32 xx 4#

#=128#

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Answer 2

#128#

Let's simplify our parenthesis first to get

#4xx8xx4#

We can multiply these now to get

#32xx4=128#

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Answer 3

To simplify (3 + 1) × 8 × 4 using the order of operations, you first perform the addition inside the parentheses, then multiply the result by 8, and finally multiply that result by 4.

(3 + 1) = 4

4 × 8 = 32

32 × 4 = 128

So, (3 + 1) × 8 × 4 simplifies to 128.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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