How do you simplify #(2x - 3)/(x + 1) + (6x + 5)/(x + 1)#?

Answer 1

#(8x+2)/(x+1)#

Add the numerators

When adding fractions, the denominators have to be the same

Here, both denominators are #x+1#, so the numerators can be added together without having to find a common denominator for both
#(2x-3+(6x+5))/(x+1)#
#(2x-3+6x+5)/(x+1) rarr# Combine like terms
#(2x+6x-3+5)/(x+1)#
#(8x+2)/(x+1)#
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Answer 2

To simplify the expression (2x - 3)/(x + 1) + (6x + 5)/(x + 1), you can combine the two fractions by finding a common denominator, which in this case is (x + 1). Then, add the numerators together and keep the common denominator. The simplified expression is (8x + 2)/(x + 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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