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How do you simplify #(2x^2-10)/(x+1)*(x+2)/(3x^2-15)#?

Answer 1

#(2(x+2))/(x+1)#

#(2x^2-10)/(x+1) * (x+2)/(3x^2-15)#

To simplify these kinds of problems, just try and factor out anything you see that is able to be factored. You need to get in the habit of just working out the problem even though you don't know what's going to happen next. Many times there are common factors that you can just divide out. #(2(cancel(x^2-5)))/(x+1) * (x+2)/(cancel(3(x^2-5)))=(2(x+2))/(x+1)#

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Answer 2

Abigail Allen

To simplify the expression (2x^2-10)/(x+1)*(x+2)/(3x^2-15), we can start by factoring the numerator and denominator.

The numerator, 2x^2-10, can be factored as 2(x^2-5).

The denominator, 3x^2-15, can be factored as 3(x^2-5).

Now, we can cancel out the common factors in the numerator and denominator.

Canceling out the 2 and the 3, we are left with (x^2-5)/(x+1)*(x+2).

This expression cannot be simplified further, so the simplified form is (x^2-5)/(x+1)*(x+2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.