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How do you simplify # -2sqrt3 * sqrt15#?

Answer 1

Ethan Adkins

-#2sqrt45#

#= -2sqrt9sqrt5#

#= -6sqrt5#

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Answer 2

Eli Assouline

To simplify -2√3 * √15, we can first simplify the square roots individually.

√3 is already simplified, so we leave it as it is.

√15 can be simplified as √(3 * 5), which is equal to √3 * √5.

Now, we can multiply the simplified square roots together:

-2√3 * √15 = -2√3 * √3 * √5

Since √3 * √3 is equal to √(3 * 3), which simplifies to √9, we have:

-2√3 * √3 * √5 = -2 * √9 * √5

√9 is equal to 3, so we have:

-2 * √9 * √5 = -2 * 3 * √5

Multiplying -2 and 3 gives us:

-2 * 3 * √5 = -6√5

Therefore, -2√3 * √15 simplifies to -6√5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.