How do you simplify #(2k)/8 + (3k)/6#?

Answer 1
Start simplifying the number in front of #k# with the denominator
#(2k)/8=(2k)/(2*4)=k/4#
#(3k)/6=(3k)/(2*3)=k/2#

Now we have

#(2k)/8+(3k)/6=k/4+k/2#
We use as common denominator #4#.
#k/4+k/2=k/4+(2k)/4#
#=(k+2k)/4#
#=(3k)/4#.

You cannot simplify more because 3 and 4 do not share any factor.

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Answer 2

To simplify (2k)/8 + (3k)/6, we need to find a common denominator for the fractions. The least common multiple of 8 and 6 is 24.

Multiplying the first fraction by 3/3 and the second fraction by 4/4, we get (6k)/24 + (12k)/24.

Combining the fractions, we have (6k + 12k)/24.

Simplifying the numerator, we get 18k/24.

The fraction can be further simplified by dividing both the numerator and denominator by their greatest common divisor, which is 6.

Thus, the simplified expression is 3k/4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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