How do you simplify #2 sqrt 7+ 3 sqrt 7+ sqrt7#?

Answer 1

#6sqrt7#

Factor a #sqrt7# from each term.
#2sqrt7+3sqrt7+sqrt7=sqrt7(2+3+1)=sqrt7(6)=6sqrt7#
Note that this is similar to addition you have likely done in the past -- try replacing each #sqrt7# with a variable like #x#.
#2x+3x+x=6x#
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Answer 2

6#sqrt7#

taking #sqrt7# common we have given expression = #sqrt7(2+3+1)# =#6sqrt7#
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Answer 3

To simplify the expression 2√7 + 3√7 + √7, you can combine the like terms. Since all the terms have the same radical (√7), you can add the coefficients together. The simplified form is (2 + 3 + 1)√7, which equals 6√7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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