How do you simplify #-2/(7r)+4/t#?

Answer 1

#=2{(-1/7r) + (2/t)}#

Taking LCM

#=2{(-t+14r)/(7rt)}#

#=(2(14r-t))/(7rt)#

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Answer 2

#-2/(7r)+4/t=color(blue)((2(14r-t))/(7rt)#

Simplify.

#-2/(7r)+4/t#

Determine the least common denominator by multplying the denominators:

#7rxxt=7rt#
Multiply each fraction by an equivalent fraction to make both denominators #7rt#. An equivalent fraction is one in which the numerator and denominator are the same. An equivalent fraction is equal to #1#. For example #8/8=1#.
The expression can be rewritten as #4/t-2/(7r)#.
#4/txxcolor(magenta)((7r)/(7r))-(2)/(7r)xxcolor(teal)(t/t#

Simplify.

#(28r)/(7rt)-(2t)/(7rt)#

Combine the numerators.

#(28r-2t)/(7rt)#
Simplify the numerator by factoring out the common #2#.
#(2(14r-t))/(7rt)#
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Answer 3

To simplify the expression -2/(7r) + 4/t, you need to find a common denominator. The common denominator is 7rt. Multiply the first term by t/t and the second term by 7r/7r. This gives you -2t/(7rt) + 28r/(7rt). Combine the terms by adding the numerators: (-2t + 28r)/(7rt). This is the simplified form of the expression.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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