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How do you simplify #2-5(9-4*sqrt(25))^2# using order of operations?

Answer 1

Eva Abramson

#2-5(9-4*sqrt25)^2=-603#

Let's make things simpler.

#2-5(9-4*sqrt25)^2" "#the given expression

#2-5(9-4(5))^2" "#we begin inside the grouping symbol exponentiation first

#2-5(9-20)^2" "#we take the product of 4 and 5

#2-5(-11)^2" "#we now have the difference between 9 and 20

#2-5(121)" "#the square of #-11# is 121

#2-605" "#the product of 121 and 5 is 605

#-603" "#final answer is the difference between 2 and 605 where 2 is the minuend and 605 the subtrahend.

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Answer 2

Julia Adams

To simplify the expression ( 2 - 5(9 - 4 \times \sqrt{25})^2 ) using the order of operations, we follow these steps:

First, we evaluate the expression inside the parentheses: ( 9 - 4 \times \sqrt{25} = 9 - 4 \times 5 = 9 - 20 = -11 ).
Next, we square the result: ( (-11)^2 = 121 ).
Then, we multiply this result by 5: ( 5 \times 121 = 605 ).
Finally, we subtract this result from 2: ( 2 - 605 = -603 ).

Therefore, the simplified expression is ( -603 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.