How do you simplify #2-3[x-2-5(x-1)]#?

Answer 1

I found: #12x-7#

First multiply #-5#: #2-3[x-2-5x+5]=# add similar terms inside the square brackets: #=2-3[3-4x]=# multiply #-3#: #=2-9+12x=# #=12x-7#

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Answer 2

Genesis Allen

To simplify (2 - 3[x - 2 - 5(x - 1)]), follow these steps:

Distribute the -5 inside the parentheses: (2 - 3[x - 2 - 5x + 5])
Combine like terms within the brackets: (2 - 3[x - 2 - 5x + 5] = 2 - 3[x - 2 - 5x + 5])
Distribute the -3 outside the brackets: (2 - 3x + 6 + 15x - 15)
Combine like terms: (2 - 3x + 6 + 15x - 15 = -3x + 15x + 2 + 6 - 15)
Combine like terms again: (-3x + 15x + 2 + 6 - 15 = 12x - 7)

So, (2 - 3[x - 2 - 5(x - 1)]) simplifies to (12x - 7).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.