How do you simplify #2^3 ÷ (7 ÷ 7 ÷ 8)# using order of operations?

Answer 1

The final answer would be 64. We figure this out through the use of BIMDAS (Brackets, Indices, Multiplication/Division, Addition/Subtraction)

Begin with what is inside the brackets #(7-:7-:8)#. This will equal 0.125 or #1/8#. This will give us #2^3-:0.125#.

Next we deal with indices, which in this case is #2^3#. If we expand this we get #2*2*2# which will equal 8.

Now we are at #8-:0.125# or #8-:1/8#

This will produce a result of 64.

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Answer 2

Hazel Anglin

To simplify (2^3 ÷ (7 ÷ 7 ÷ 8)) using the order of operations (PEMDAS/BODMAS), follow these steps:

Perform operations inside parentheses first: (7 ÷ 7 = 1).
Then, simplify (1 ÷ 8 = \frac{1}{8}).
Next, simplify (2^3 = 2 \times 2 \times 2 = 8).
Finally, divide (8) by (\frac{1}{8}): (8 ÷ \frac{1}{8} = 8 \times 8 = 64).

So, (2^3 ÷ (7 ÷ 7 ÷ 8) = 64).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.