# How do you simplify #2[3(3x +1)+ 2( 2x +5)] + 3[1+ 4(x+2)+5x]#?

Notice that there are 2 terms. Start my removing the brackets within each term using the distributive law

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To simplify the expression 2[3(3x + 1) + 2(2x + 5)] + 3[1 + 4(x + 2) + 5x], follow the order of operations (PEMDAS/BODMAS):

Step 1: Simplify the expressions within the innermost parentheses. 3(3x + 1) = 9x + 3 2(2x + 5) = 4x + 10 4(x + 2) = 4x + 8

Step 2: Simplify the expressions within the brackets. 2[9x + 3 + 4x + 10] = 2[13x + 13] 3[1 + 4x + 8 + 5x] = 3[9x + 9]

Step 3: Simplify the expressions within the outermost brackets. 2[13x + 13] = 26x + 26 3[9x + 9] = 27x + 27

Step 4: Combine like terms. 26x + 26 + 27x + 27 = 53x + 53

Therefore, the simplified expression is 53x + 53.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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