How do you simplify 2√3 (√3 - 1 )?

Answer 1

Nathan Axel

#6-2sqrt3#

Distributing #2sqrt3# to the parenthesis, we now have

#2color(blue)(sqrt3sqrt3)-2sqrt3#

This simplifies to

#2*color(blue)3-2sqrt3#

#=>6-2sqrt3#

Hope this helps!

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Answer 2

Isaiah Anthony

#2\sqrt3(\sqrt3-1)#

#=(2\sqrt3)\sqrt3-2\sqrt3#

#=2(\sqrt3\sqrt3)-2\sqrt3#

#=2(3)-2\sqrt3#

#=6-2\sqrt3#

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Answer 3

Julia Adams

See a solution process below:

Expand the term in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(2sqrt(3))(sqrt(3) - 1) =>#

#(color(red)(2sqrt(3)) xx sqrt(3)) - (color(red)(2sqrt(3)) xx 1) =>#

#color(red)(2)(sqrt(3))^2 - 2sqrt(3) =>#

#(color(red)(2) xx 3) - 2sqrt(3) =>#

#6 - 2sqrt(3)#

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Answer 4

Hazel Anglin

To simplify 2√3 (√3 - 1), you can distribute the 2√3 to both terms inside the parentheses. This gives you 2√3 * √3 - 2√3 * 1. Simplifying further, you have 2√(3 * 3) - 2√3. This simplifies to 2√9 - 2√3. Since √9 is equal to 3, the expression becomes 2 * 3 - 2√3, which simplifies to 6 - 2√3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.