How do you simplify #17– 6 xx 10 ÷ 2 + 12#?

Answer 1

#color(purple)(=> -1)#

#17 - 6 xx 10 / 2 + 12#

Using PEMDAS rule,

#=> 17 - 60 / 2 + 12#, multiplying
#=> 17 - 30 + 12#, dividing
#=> 17 + 12 - 30#, rearranging terms
#=> 29 - 30#, adding
#color(purple)(=> -1#, subtracting
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Answer 2

#-1#

Identify the number of terms first. Each term will simplify to a single answer which can be added or subtracted in the last step.

#color(blue)(17)" " color(red)(- 6xx10div2) color(green)(" " +12)" "larr# there are 3 terms

Within each term the order of operations is:

#=color(blue)(17)" " color(red)(- (cancel6^3xx10)/cancel2) color(green)(" " +12)#
#=color(blue)(17)" " color(red)(-30) color(green)(" " +12)#

You will make fewer mistakes if you write the additions at the beginning and subtractions at the end.

#=color(blue)(17)" " color(green)( +12)" "color(red)(- 30)#
#=29" "color(red)(- 30)#
#=-1#
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Answer 3
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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