How do you simplify #(1- i ) - ( 3- 1) ( 3+ 1)#?

Answer 1

#(1-i)-(3-1)(3+1)=-7#

The P in PEMDAS stands for parentheses, so do what you can in parentheses first: You can't simplify #(1-i)# since #i# isn't a real number. #3-1=2#, and #3+1=4#, so we can rewrite the expression: #(1-i)-(3-1)(3+1)=(1-i)-(2)(4)# Multiplication and Division come before addition and subtraction in the order of operations, so multiply #2*4=8#. Now the expression is #(1-i)-8#. Again, we can't combine that #i# with a real number, but we know that #1-8=-7#. So our final result is #(1-i)-8=1-i-8=-7-i#
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Answer 2

To simplify the expression (1 - i) - (3 - 1) (3 + 1), you can follow these steps:

  1. Expand the expression inside the parentheses: (3 - 1) (3 + 1) = (2)(4) = 8.
  2. Rewrite the original expression with the expanded result: (1 - i) - 8.
  3. Combine like terms: 1 - i - 8.
  4. Perform the subtraction: 1 - 8 = -7.
  5. The simplified expression is -7 - i.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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