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How do you simplify #-1/2(7z+4)+1/5(5z-16)#?

Answer 1

Isaiah Anthony

#(-5/2)z - 26/5#

You must first enlarge the terms inside the parenthesis in order to simplify this expression:

#(-7/2)x - (4/2) + (5/5)z - (16/5)#

#(-7/2)z - 2 + z - (16/5)#

Next, group similar terms together by obtaining common denominators:

#(-7/2)z + (2/2)z - (10/5) - (16/5)#

#(-5/2)z - 26/5#

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Answer 2

Julia Adams

To simplify (-\frac{1}{2}(7z+4) + \frac{1}{5}(5z-16)), distribute the coefficients:

(-\frac{1}{2} \cdot 7z - \frac{1}{2} \cdot 4 + \frac{1}{5} \cdot 5z - \frac{1}{5} \cdot 16)

Simplify each term:

(-\frac{7}{2}z - 2 + z - \frac{16}{5})

Combine like terms:

(-\frac{7}{2}z + z - 2 - \frac{16}{5})

Combine (z) terms:

(-\frac{7}{2}z + z = \frac{-7 + 10}{2}z = \frac{3}{2}z)

Combine constant terms:

(-2 - \frac{16}{5} = \frac{-10 - 16}{5} = \frac{-26}{5})

So, the simplified expression is (\frac{3}{2}z - \frac{26}{5}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.