How do you rewrite #w=3(2a + b)  4# to solve for #a#?
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To rewrite ( w = 3(2a + b)  4 ) to solve for ( a ), follow these steps:

Expand the expression inside the parentheses: [ 2a + b ]

Multiply (3) by the result of the expansion: [ 3(2a + b) ]

Subtract (4) from the previous result: [ 3(2a + b)  4 ]

Distribute (3) across (2a) and (b): [ 6a + 3b  4 ]

Move terms not containing (a) to the right side of the equation: [ 6a = w  3b + 4 ]

Finally, divide both sides by (6) to isolate (a): [ a = \frac{w  3b + 4}{6} ]
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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