Home > Algebra > Vertex Form of a Quadratic Equation

How do you rewrite the following quadratic equation in vertex form: #y=x^2-8x+13#?

Answer 1

minimum vertex with value#- 3# at #(4, -3)#

#y = x^2 - 8 x + 13#

Consider coefficient of #x#, divide by 2 and make a parentesis and ssquare them. since infront of parentesis is +ve value, then deduct the squared number in parentesis in the equation to balance it. #y = (x - 4)^2 - (-4)^2 + 13# #y = (x - 4)^2 - 16 + 13# #y = (x - 4)^2 - 3#

since infront of #(x-4)^2# is +ve sign, it is a minimum vertex with value#- 3# at #(4, -3)#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eva Adamson

To rewrite the quadratic equation (y = x^2 - 8x + 13) in vertex form:

Complete the square by adding and subtracting the square of half the coefficient of (x): [y = x^2 - 8x + 13] [y = (x^2 - 8x + \underline{16}) - 16 + 13]
Simplify the equation: [y = (x - 4)^2 - 3]

Thus, the vertex form of the quadratic equation (y = x^2 - 8x + 13) is (y = (x - 4)^2 - 3).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.