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How do you rewrite #(7ab^-2)/(3x)# using a positive exponent?

Answer 1

Nathan Axel

#(7ab^(-2))/(3x) = (7a)/(3b^2x)#

#b^3 = b xx b xx b#

#b^2 = b^3/b = b xx b#

#b^1 = b^2/b = b#

#b^0 = b^1/b = 1#

#b^(-1) = b^0/b = 1/b#

#b^(-2) = b^(-1)/b = (1/b)/b = 1/b^2#

And in other news: #(7ab^(-2))/(3x) = (7a)/(3x) * b^(-2)#

#color(white)("XXXX") = (7a)/(3x)*1/b^2#

#color(white)("XXXX") = (7a)/(3xb^2)#

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Answer 2

Eli Assouline

To rewrite (\frac{7ab^{-2}}{3x}) using a positive exponent, you need to move the term with the negative exponent to the denominator.

So, the expression becomes (\frac{7a}{3xb^2}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.