How do you reduce #96/108# in lowest terms?

Answer 1

#96/108=8/9#

#96/108#
= #(2xx2xx2xx2xx2xx3)/(2xx2xx3xx3xx3)#
= #(2xx2xx2xxcancel(2xx2xx3))/(cancel(2xx2xx3)xx3xx3)#
= #(2xx2xx2)/(3xx3)#
= #8/9#
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Answer 2

To reduce ( \frac{96}{108} ) to its lowest terms, we need to find the greatest common divisor (GCD) of the numerator and the denominator, which is the largest number that divides both numbers evenly.

The prime factorization of 96 is ( 2^5 \times 3 ), and the prime factorization of 108 is ( 2^2 \times 3^3 ).

To find the GCD, we look for the highest power of each prime factor that appears in both factorizations. In this case, the common factor is ( 2^2 \times 3 ).

So, ( \text{GCD}(96, 108) = 2^2 \times 3 = 12 ).

To simplify the fraction, we divide both the numerator and the denominator by the GCD:

[ \frac{96}{108} = \frac{96 \div 12}{108 \div 12} = \frac{8}{9} ]

Therefore, ( \frac{96}{108} ) in its lowest terms is ( \frac{8}{9} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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