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How do you reduce #7y + 2y^2 - 7# by #3 - 4y#?

Answer 1

Nathan Axel

#11y +2y^2-10# is #(3-4y)# less than #7y+2y^2-7#;
that is, if you reduce #7y+2y^2-7# by #3-4y# you get #11y+2y^2-10#

The phrasing is a little unusual but "reducing" A by B means subtracting B from A.

#(color(red)(7y+2y^2-7)) - (color(blue)(3-4y))#

#=color(red)(7y)color(blue)(+4y) + 2y^2 color(red)(-7) color(blue)(-3)#

#=11y - 2y^2 -10#

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Answer 2

Eli Assouline

To reduce ( 7y + 2y^2 - 7 ) by ( 3 - 4y ), you perform polynomial division or use the long division method. The result is ( -2y - 1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.