How do you rationalize the denominator and simplify # sqrt30/sqrt5#?

Answer 1

Julia Adams

#sqrt(6)#

We have: #sqrt(30)/sqrt(5)#

Let's begin by expressing the numerator as a product of two radicals:

#=(sqrt(6)timessqrt(5))/sqrt(5)#

We can then simlify this expression by cancelling the #sqrt(5)# terms:

#=sqrt(6)#

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Answer 2

Avery Alexander

The value of this expression is #sqrt(6)#. See explanation.

You can easily see that #30=5*6#, so

#sqrt(30)/sqrt(6)=sqrt(5*6)/sqrt(5)=(sqrt(5)*sqrt(6))/sqrt(5)=sqrt(6)#

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Answer 3

Avery Alexander

To rationalize the denominator and simplify the expression sqrt30/sqrt5, we can multiply both the numerator and denominator by sqrt5. This gives us (sqrt30/sqrt5) * (sqrt5/sqrt5) = sqrt(305)/sqrt(55) = sqrt(150)/sqrt(25) = sqrt(150)/5. Therefore, the simplified expression is sqrt(150)/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.