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How do you prove #tan^2xsin^2x=tan^2x + cos^2x-1#?

Answer 1

Delilah Aguilar

#tan^2 x .sin^2 x = tan^2 x(1 - cos^2 x) = tan^2 x - tan^2 x(cos^2 x)#

#= tan^2 x - (sin^2 x.cos^2 x)/(cos^2 x) = tan^2 x - sin^2 x =#

#= tan^2x - 1 + cos^2 x#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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