How do you prove #secx+sin^2x+cos^2x=secx#?

Answer 1

This cannot be proven.

The first thing that should be recognized is the #sin^2x+cos^2x# term.
This is the Pythagorean Identity: #sin^2x+cos^2x=1#

As a result, the equation can be changed to:

#secx+(sin^2x+cos^2x)=secx#
#secx+1=secx#
#0!=1#

This equation is invalid as an identity and has no solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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