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How do you order the following from least to greatest #-sqrt1, 0.1, sqrt13, -3/5, sqrt6#?

Answer 1

Genesis Allen

#-sqrt(1), -3/5, 0.1, sqrt(6), sqrt(13)#

Negative numbers are the smallest, so we need to pick between #-sqrt(1) = -1, " and "-3/5 = -.6#.

Since #-5/5 = -1, -3/5 " must be greater than " -1#

Since #sqrt(1) = 1, 0.1 < sqrt(1) < sqrt(6) < sqrt(13)#

Furthermore,

#sqrt(4) = 2# so #sqrt(6) > sqrt(4)#

From a calculator #sqrt(6) ~~ 2.4495#

From a calculator #sqrt(13) ~~ 3.61#

So from least to greatest: #-sqrt(1), -3/5, 0.1, sqrt(6), sqrt(13)#

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Answer 2

Kennedy Adams

To order the given numbers from least to greatest, we first need to evaluate each of them:

( -\sqrt{1} = -1 )
( 0.1 )
( \sqrt{13} ) is approximately ( 3.606 )
( -\frac{3}{5} = -0.6 )
( \sqrt{6} ) is approximately ( 2.449 )

Ordering them:

( -1 )
( -0.6 )
( 0.1 )
( 2.449 )
( 3.606 )

So, from least to greatest, the order is ( -1, -\frac{3}{5}, 0.1, \sqrt{6}, \sqrt{13} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.