How do you optimize #f(x,y)=2x^2+3y^2-4x-5# subject to #x^2+y^2=81#?
Maximum is 242, at
There is no minimum.
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To optimize the function (f(x, y) = 2x^2 + 3y^2 - 4x - 5) subject to the constraint (x^2 + y^2 = 81), we can use the method of Lagrange multipliers.
- Define the Lagrangian function:
[L(x, y, \lambda) = f(x, y) - \lambda(g(x, y) - 81)]
where (g(x, y) = x^2 + y^2).
- Calculate the partial derivatives of the Lagrangian with respect to (x), (y), and (\lambda) and set them to zero:
[\frac{\partial L}{\partial x} = 4x - 4 - 2\lambda x = 0]
[\frac{\partial L}{\partial y} = 6y - 3 - 2\lambda y = 0]
[\frac{\partial L}{\partial \lambda} = x^2 + y^2 - 81 = 0]
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Solve the system of equations to find the critical points.
-
Check the endpoints of the region (in this case, the circle (x^2 + y^2 = 81)) to see if they yield a maximum or minimum.
-
Evaluate the function at the critical points and the endpoints to determine the maximum and minimum values of (f(x, y)) subject to the constraint.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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