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How do you normalize # <3,1,5>#?

Answer 1

William Audy

#<3/sqrt35,1/sqrt35,5/sqrt35>#

First, you have to calculate for the magnitude of the vector .

#||v||=sqrt(3^2+1^2+5^2)=sqrt35#

Second, divide the magnitude by each of the component of the vector.

#1/sqrt35 <3,1,5> = <3/sqrt35,1/sqrt35,5/sqrt35>#

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Answer 2

Xavier Adame

To normalize the vector <3, 1, 5>, you would divide each component of the vector by the magnitude of the vector. Magnitude of the vector = √(3^2 + 1^2 + 5^2) = √(9 + 1 + 25) = √35 Normalized vector = <3/√35, 1/√35, 5/√35>

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you normalize # &lt;3,1,5&gt;#?

How do you normalize # <3,1,5>#?