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How do you multiply #(x + y + 3)(x + y - 4)#?

Answer 1

Savannah Anderson

The Expression#=x^2+2xy+y^2-x-y-12#.

Letting #x+y=z#, we find that,

The Expression#=(z+3)(z-4)=z(z-4)+3(z-4)=z^2-4z+3z-12#

#=z^2-z-12#

Surrendering #z=x+y#, we get,

The Expression#=(x+y)^2-x-y-12#

#=x^2+2xy+y^2-x-y-12#.

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Answer 2

Eva Abramson

To multiply (x + y + 3)(x + y - 4), you apply the distributive property and then combine like terms:

(x + y + 3)(x + y - 4) = x(x + y - 4) + y(x + y - 4) + 3(x + y - 4) = x^2 + xy - 4x + xy + y^2 - 4y + 3x + 3y - 12 = x^2 + 2xy - x - y^2 - y - 12

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.