How do you multiply #(x-5)^2#?

Answer 1

#x^2-10x+25#

We got: #(x-5)^2#
A fundamental rule in algebra is that #(a-b)^2=a^2-2ab+b^2#, and #(a+b)^2=a^2+2ab+b^2#.

But since we have a minus sign, we use the former one.

So, we plug in #a=x,b=5#, and we get:
#x^2-2*x*5+5^2#
#=x^2-10x+25#
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Answer 2

To multiply (x-5)^2, you apply the distributive property twice, expanding the expression. This results in (x-5)(x-5), which can be simplified to x^2 - 10x + 25.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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