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How do you multiply #(x+2)(7x+8)#?

Answer 1

Eva Adamson

#7x^2+22x+16#

You simply expand the brackets like this: #x*7x+x*8+2*7x+2*8# Which gives the answer of: #7x^2+22x+16#

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Answer 2

Genesis Allen

Expand the parentheses to get 4 terms

Expand the brackets to get #7x^2+14x+8x+16# = #7x^2+22x+16#

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Answer 3

Hazel Anglin

To multiply ((x+2)(7x+8)), you can use the distributive property or the FOIL method:

Using the distributive property: [ (x+2)(7x+8) = x(7x) + x(8) + 2(7x) + 2(8) ]

[ = 7x^2 + 8x + 14x + 16 ]

[ = 7x^2 + 22x + 16 ]

Using the FOIL method: [ (x+2)(7x+8) = x \cdot 7x + x \cdot 8 + 2 \cdot 7x + 2 \cdot 8 ]

[ = 7x^2 + 8x + 14x + 16 ]

[ = 7x^2 + 22x + 16 ]

So, ( (x+2)(7x+8) = 7x^2 + 22x + 16 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.