How do you multiply #(x + -1x^2)(x^2 + -1x)#?

Answer 1

Isaiah Anthony

#-x^4+2x^3-x^2#

Note that

#x+-x^2=x-x^2# and

#x^2+-x=x^2-x#

So we get

(x-x^2)(x^2-x)=-(x^2-x)(x^2-x)=-(x^2-x)^2#

Using that #(a+b)^2=a^2+2ab+b^2#

we obtain

#-(x^4-2x^3+x^2)=-x^4+2x^3-x^2#

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Answer 2

Avery Alexander

To multiply (x + -1x^2) and (x^2 + -1x), you can use the distributive property and combine like terms.

(x + -1x^2)(x^2 + -1x) = x * x^2 + x * (-1x) + (-1x^2) * x^2 + (-1x^2) * (-1x) = x^3 - x^2 + (-1x^4) + x^3 = -x^2 + 2x^3 - x^4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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