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How do you multiply #(t^2+5t)/(t+1)div(t+5)#?

Answer 1

#t/(t+1)#

With the statement #(t^2+5t)/(t+1) -: (t+5)#, let's first see that we can factor the numerator on the left-hand side. The other thing to notice is that when we have something in the form of #a/b -: c/d#, it can be restated as #a/b xx d/c#, and so:

#(t^2+5t)/(t+1) -: (t+5)/1#

#(t(t+5))/(t+1) xx 1/(t+5)#

And now we can cancel:

#(t(cancel(t+5)))/(t+1) xx 1/cancel(t+5)#

#t/(t+1)#

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Answer 2

Eva Abramson

To multiply (t^2+5t)/(t+1) by (t+5), you can use the distributive property. First, distribute (t+5) to both terms in the numerator of (t^2+5t)/(t+1). This results in (t^2+5t)*(t+5)/(t+1). Next, you can simplify the numerator by multiplying the terms using the distributive property and combining like terms. Finally, divide the simplified numerator by (t+1) to get the final result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.