How do you multiply #[sqrt(2) + sqrt(7)]*[sqrt(3) - sqrt(7)]#?

Answer 1

Genesis Allen

Use the FOIL method for multiplying two binomials.

The FOIL method for multiplying two binomials indicates the order in which the terms should by multiplied.

#(sqrt2+sqrt7)(sqrt3-sqrt7)# =

#sqrt2sqrt3-sqrt2sqrt7+sqrt7sqrt3-sqrt7sqrt7# =

#sqrt6-sqrt14+sqrt21-7#

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Answer 2

Hazel Anglin

To multiply [sqrt(2) + sqrt(7)]*[sqrt(3) - sqrt(7)], you can use the distributive property. Multiply the first terms together, then multiply the outer terms, the inner terms, and finally the last terms. Simplify the resulting expression by combining like terms and simplifying any square roots. The final answer is sqrt(6) - sqrt(14) - sqrt(21) + 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.