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How do you multiply #(h^2)/(32h - 64) * 16/(h^4 - 5h^2)#?

Answer 1

Abigail Allen

#=1/(2(h-2)(h^2-5)#

First factorize both denominators (in this case by taking out common factors) and see if some terms maybe cancel :

#(h^2)/(32(h-2))*16/(h^2(h^2-5)#

#=1/(2(h-2)(h^2-5)#

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Answer 2

Genesis Allen

To multiply the given expressions, you need to multiply the numerators together and the denominators together.

The numerator will be (h^2) * 16, which simplifies to 16h^2.

The denominator will be (32h - 64) * (h^4 - 5h^2).

To simplify the denominator, you can factor out common terms.

The denominator can be rewritten as 32(h - 2) * h^2(h^2 - 5).

Therefore, the final expression is (16h^2) / (32(h - 2) * h^2(h^2 - 5)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.