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How do you multiply #(c^4+c^2)(c^4-c^2)#?

Answer 1

Eva Abramson

#(c^4+c^2)(c^4-c^2)=color(blue)(c^8-c^4#

Multiply (Expand):

#(c^4+c^2)(c^4-c^2)#

Use the difference of squares:

#a^2-b^2=(a+b)(a-b),#

where:

#a=c^4# and #b=c^2#.

#(c^4)^2-(c^2)^2#

Apply power rule: #(a^m)^n=a^(m*n)#

#c^(4*2)-c^(2*2)#

Simplify.

#c^8-c^4#

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Answer 2

Savannah Anderson

To multiply (c^4+c^2)(c^4-c^2), you can use the difference of squares formula, which states that for any real numbers a and b: (a^2 - b^2) = (a + b)(a - b). Applying this formula to the given expression:

(c^4+c^2)(c^4-c^2) = (c^4)^2 - (c^2)^2

Simplify each term:

= c^8 - c^4

So, (c^4+c^2)(c^4-c^2) simplifies to c^8 - c^4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.