How do you multiply #(b^2-6n+9)/(b^2-b-6)div(b^2-9)/4#?
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To multiply the given expression, you need to follow these steps:
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Factorize the numerator and denominator of the first fraction: (b^2 - 6n + 9) = (b - 3)(b - 3) (b^2 - b - 6) = (b - 3)(b + 2)
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Factorize the numerator of the second fraction: (b^2 - 9) = (b - 3)(b + 3)
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Rewrite the division as multiplication by taking the reciprocal of the second fraction: (b^2 - 6n + 9)/(b^2 - b - 6) ÷ (b^2 - 9)/4 becomes (b^2 - 6n + 9)/(b^2 - b - 6) * 4/(b^2 - 9)
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Cancel out common factors between the numerators and denominators: (b - 3)(b - 3)/(b - 3)(b + 2) * 4/(b - 3)(b + 3)
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Simplify the expression by canceling out common factors: (b - 3)/(b + 2) * 4/(b + 3)
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Multiply the numerators and denominators together: (b - 3)(4) / (b + 2)(b + 3)
Therefore, the simplified expression is (b - 3)(4) / (b + 2)(b + 3).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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