How do you multiply #(8x + 9)(8x + 3) #?

Answer 1

#64x^2 + 96x + 27#

We have, #y = (8x + 9) (8x + 3)#
#implies y = 8x(8x + 9) +3 (8x + 9)#
#implies y = 64x^2 + 72x + 24x + 27#

Collect like terms

#y = 64x^2 + (72x + 24x) + 27#
#implies y = 64x^2 + 96x + 27#

Therefore,

#(8x + 9) (8x + 3) = 64x^2 + 96x + 27#
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Answer 2

To multiply the expressions ((8x + 9)(8x + 3)), you can use the distributive property or the FOIL method.

Using the distributive property:

((8x + 9)(8x + 3) = 8x \times (8x + 3) + 9 \times (8x + 3))

Expanding each term:

(= 8x \times 8x + 8x \times 3 + 9 \times 8x + 9 \times 3)

(= 64x^2 + 24x + 72x + 27)

(= 64x^2 + (24x + 72x) + 27)

(= 64x^2 + 96x + 27)

Using the FOIL method:

((8x + 9)(8x + 3) = (8x \times 8x) + (8x \times 3) + (9 \times 8x) + (9 \times 3))

(= 64x^2 + 24x + 72x + 27)

(= 64x^2 + (24x + 72x) + 27)

(= 64x^2 + 96x + 27)

Therefore, the product of ((8x + 9)(8x + 3)) is (64x^2 + 96x + 27).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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