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How do you multiply #(8a^4b^3)/(3c) div (a^7b^2)/(9c)#?

Answer 1

#(24 b) /a^3#

#(( 8a^4×b^3)/3c ) ÷ ((a^7×b^2)/9c)# =#((8a^4×b^3)/3c) × (9c/(a^7×b^2))# =#(8×3×a^4×b^3)/(a^7×b²)# =#(24×b)/a^3# =#(24b)/a^3 #

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Answer 2

Eva Abramson

To multiply the given expression, we can simplify it by dividing the numerator of the first fraction by the denominator of the second fraction, and vice versa. This can be done by multiplying the numerators together and the denominators together.

So, the simplified expression is:

(8a^4b^3)/(3c) * (9c)/(a^7b^2)

Multiplying the numerators gives us:

8a^4b^3 * 9c

And multiplying the denominators gives us:

3c * a^7b^2

Combining like terms, we get:

72a^4b^3c / 3ac * a^7b^2

Simplifying further, we can cancel out common factors:

72a^4b^3c / 3ac * a^7b^2 = 24a^3 * a^6 * b * b^2 / 1

Finally, simplifying the expression gives us:

24a^9b^3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.