How do you multiply #(5y - 3) ( 5y - 8)#?

Question

Hazel Anglin · Accepted Answer

See explanation.

To multiply 2 polynomials you have to multiply each term in one of the polynomials by each term of the other and then reduce the like terms:

Ethan Adkins · Answer

#25y^2-55y+24#

#color(blue)((5y-3)(5y-8)#

We can use the FOIL method to solve this

Now multiply the firsts

#rarr5yxx5y=25y^2#

Now multiply the outers

#rarr5yxx-8=-40y#

Now multiply the inners

#rarr-3xx5y=-15y#

Now multiply the lasts

#rarr-3xx-8=24#

Now put them all together

#rarr25y^2-40y-15y+24#

#color(green)(rArr25y^2-55y+24#

Hope that helps!!! ☺•☻

Kennedy Adams · Answer

Given: #color(blue)((5y-3)) color(green)( (5y-8) ) # Multiply everything in the right brackets by everything in the left.
Note that the minus in #color(blue)(-3)# follows the three. #color(green)(color(blue)(5y)(5y-8)  color(blue)(color(white)("ddd")-color(white)("ddd")3)(5y-8)) # #25y^2-40ycolor(white)("ddddd") - 15y+24# #25y^2-55y+24#

Genesis Allen · Answer

#color(magenta)(25y^2-55y+24# #(5y-3)(5y-8)# #color(white)(aaaaaaaaaaaaaa)##5y-3# #color(white)(aaaaaaaaaaa)## xx underline(5y-8)# #color(white)(aaaaaaaaaaaaa)##25y^2-15y# #color(white)(aaaaaaaaaaaaaaaaa)##-40y+24# #color(white)(aaaaaaaaaaaaa)##overline(25y^2-55y+24)# #color(white)(aaaaaaaaaaaaa)##color(magenta)(25y^2-55y+24#

Isaiah Anthony · Answer

undefined To multiply $ (5y - 3) \times (5y - 8) $, you can use the distributive property or the FOIL method.

Distributive property: 
$$ (a + b) \times (c + d) = a \times c + a \times d + b \times c + b \times d $$

FOIL method:
$$ (a + b) \times (c + d) = ac + ad + bc + bd $$

In your case:
$$ (5y - 3) \times (5y - 8) $$

Using the FOIL method:
$$ (5y \times 5y) + (5y \times -8) + (-3 \times 5y) + (-3 \times -8) $$

$$ = 25y^2 - 40y - 15y + 24 $$

$$ = 25y^2 - 55y + 24 $$

So, $ (5y - 3) \times (5y - 8) = 25y^2 - 55y + 24 $.