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How do you multiply #(5x+3)(-x+4)#?

Answer 1

Eli Assouline

#-5x^2+17x+12#

#"each term in the second bracket is multiplied by each "# #"term in the first bracket"#

#(color(red)(5x+3))(-x+4)#

#=color(red)(5x)(-x+4)color(red)(+3)(-x+4)#

#=(color(red)(5x)xx-x)+(color(red)(5x)xx4)+(color(red)(3)xx-x)+(color(red)(3)xx4)#

#=-5x^2+20x-3x+12#

#=-5x^2+17x+12#

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Answer 2

Nathan Axel

To multiply (5x + 3)(-x + 4), you can use the distributive property or the FOIL method. Distribute each term in the first expression to each term in the second expression, then combine like terms:

(5x + 3)(-x + 4) = 5x * (-x) + 5x * 4 + 3 * (-x) + 3 * 4

= -5x^2 + 20x - 3x + 12

= -5x^2 + 17x + 12

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.