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How do you multiply #(5 + x)(2x + -10)#?

Answer 1

Genesis Allen

#2x^2-50#

#(5+x)(2x+ -10)#

It must be written as

#(5+x)[2x+ (-10)]#

Remove the inner most bracket

#(5+x)[2x -10]#

Now Multiply

#10x+2x^2-50-10x#

#2x^2-50#

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Answer 2

Abigail Allen

To multiply (5 + x)(2x + -10), you can use the distributive property or the FOIL method:

First, distribute each term in the first parentheses to each term in the second parentheses:

5(2x) + 5(-10) + x(2x) + x(-10)

Then, simplify each term:

10x + (-50) + 2x^2 + (-10x)

Combine like terms:

2x^2 + (10x - 10x) + (-50)

The middle terms cancel out:

2x^2 - 50

So, the result is 2x^2 - 50.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.