How do you multiply #(5.8\times 10^ { - 6} ) ( 3\times 10^ { - 8} )#?

Answer 1

#(5.8xx10^(-6))(3xx10^(-8))=1.74xx10^(-13)#

We are multipying two numbers given in scientific notation and it is expected to give result too in scientific notation.

So #(5.8xx10^(-6))(3xx10^(-8))#
= #(5.8xx3)xx(10^(-6)xx10^(-8))#
= #17.4xx10^(-6+(-8))#
= #(1.74xx10)xx10^(-14)#
= #1.74xx10^(1-14)#
= #1.74xx10^(-13)#
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Answer 2

To multiply numbers in scientific notation, you multiply the coefficients and add the exponents.

So, ( (5.8 \times 10^{-6}) \times (3 \times 10^{-8}) ) would be:

( (5.8 \times 3) \times 10^{(-6 + (-8))} )

( = 17.4 \times 10^{-14} )

( = 1.74 \times 10^{-13} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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