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How do you multiply #(4y)/7divy^2/14*3/y#?

Answer 1

Hazel Anglin

See below.

#x/y\dividea/b=x/y\cdotb/a#

#(4y)/7divy^2/14*3/y=(4y)/7\cdot14/y^2*3/y#

#(4y)/7\cdot14/y^2*3/y=(4y*14*3)/(7*y^2*y)=(4*14*3)/(7*y^2)=(4*2*3)/(y^2)=(24)/(y^2)#

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Answer 2

Jameson Allen

To multiply (4y)/7 divided by y^2/14 multiplied by 3/y, you can follow these steps:

Simplify the expression by canceling out common factors:
- In the numerator, cancel out the common factor of y between (4y) and y^2, leaving 4/y.
- In the denominator, cancel out the common factor of 7 between 7 and y^2, leaving y^2/1.
- In the denominator, cancel out the common factor of y between y and 3, leaving 3/1.
Multiply the remaining factors:
- Multiply the numerators: 4 * 3 = 12.
- Multiply the denominators: y * y^2 = y^3.
Simplify the expression further if possible:
- The final expression is 12/y^3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.