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How do you multiply #(4x)/3*(8x)/2# and state the excluded values?

Answer 1

#(4x)/3xx(8x)/2=(16x^2)/3#

Such fractions may be mulitplied directly, #"numerator"xx"numerator"# and #"denominator"xx"deominator"#. And we can divide thru by common factors.

So #(4x)/3xx(8x)/2=(4x xx8x)/(3xx2)=(cancel2xx2x xx8x)/(3xxcancel2)=(16x^2)/3#

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Answer 2

Eli Assouline

To multiply (4x)/3*(8x)/2, you can simplify the expression by multiplying the numerators and denominators separately.

First, multiply the numerators: (4x)*(8x) = 32x^2.

Next, multiply the denominators: 3*2 = 6.

The simplified expression is (32x^2)/6, which can be further simplified to (16x^2)/3.

The excluded values are any values of x that would make the denominator equal to zero. In this case, x cannot be equal to zero, as it would result in division by zero.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.